Question

U
C
D
F
3 In the adjoining figure, ABCD is a parallelogram. E and
F are mid-points of the sides AB and CD respectively.
The straight lines AF and BF meet the straight lines ED
and EC in points G and H respectively. Prove that
(1) AHEB = AHCF
G
ΚΗ
(ii) GEHF is a parallelogram.
A
E
B​

Answer 1

Answer:

May I know where is your adjoining figure???

Pls attach the figure also or modify your question...