Question

u can sol it trignometry​

Answer 1

Answer:

sinA = 2 tanA/Sec^2A

= 2/Cota ( 1+ 1/Cot^2A)

= 2 cot^2 a/cota ( cot^2 + 1)

= 2 cot/(1+ cot^2a)

secA = 1 + 1/cot^2a

= (cot^2 a + 1)/cot^2 a

tana = 1/cota

Answer 2

Following Trigonometric functions are represented in terms of CotA

1)tan A:

tanA=1/cotA.

2)SecA:

sec^2A =1+tan^2A

implies SecA =root(1+tan^2A)

which implies SecA=root(cot^2A+1)/cotA

SinA:

SinA=1/cosecA

we know 1+cot^2A=cosec^2A

implies CosecA=root(1+cot^2A)

therefore SinA becomes 1/root(1+cot^2A)..