Math, asked by rahul643, 1 year ago

u can tell this one ans qs 4

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Answered by Johncena9090
1
Area of Rhombus = ( 1 / 2 ) * ( d1 * d2 ) Where, d1 and d2 are Diagonals Given, Area of Rhombus = 1080 Let d1 = 72 Area of Rhombus = ( 1 / 2 ) * ( 72 * d2 ) Area of Rhombus = ( 36 * d2 ) = 1080 ( 36 * d2 ) = 1080 ( d2 ) = 1080 / 36 d2 = 30 Perimeter of a Rhombus = 2 * ? ( p² + q² ) Where, p and q are Diagonals of a Rhombus p =72 q = 30 Perimeter of a Rhombus = 2 * ? ( 72² + 30² ) = 2 * ? ( 5184 + 900 ) = 2 * ? ( 6084 ) = 2 * 78 =156

Johncena9090: then the diagonals of a rhombus bisect perpendicularly
Johncena9090: so by using pythogoras theorem find its one side
Johncena9090: then find its perimeter
Johncena9090: hope this helps you...
rahul643: is said how 78 comes
rahul643: tell plz
Johncena9090: ok
Johncena9090: it is √6084
rahul643: thz
Johncena9090: welcome
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