u can tell this one ans qs 4
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Area of Rhombus = ( 1 / 2 ) * ( d1 * d2 ) Where, d1 and d2 are Diagonals Given, Area of Rhombus = 1080 Let d1 = 72 Area of Rhombus = ( 1 / 2 ) * ( 72 * d2 ) Area of Rhombus = ( 36 * d2 ) = 1080 ( 36 * d2 ) = 1080 ( d2 ) = 1080 / 36 d2 = 30 Perimeter of a Rhombus = 2 * ? ( p² + q² ) Where, p and q are Diagonals of a Rhombus p =72 q = 30 Perimeter of a Rhombus = 2 * ? ( 72² + 30² ) = 2 * ? ( 5184 + 900 ) = 2 * ? ( 6084 ) = 2 * 78 =156
Johncena9090:
then the diagonals of a rhombus bisect perpendicularly
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