u find the value of k if one zero of
P(= kx²+3 x+ is 2.
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Answer:
k=-3/2
Step-by-step explanation:
Given that:
p(x) = kx²+3x
p(2)=0
To find : the value of k
p(2)= k(2)²+3(2) = 0
p(2) = 4k+6 = 0
4k+6=0
k=-3/2
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