Question

U solve one problem.
There are two cans of seven n
ten litres n one can of ten litres
is full water n another seven is
empty.
There is a one measurement of
three litres only two use
So divide five litres in each can
using three litre measurement
only none other than n there
should not be no one drop less or
variation​

Answer 1

Answer:

$\huge\mathcal\blue{Question}$

There are two cans of seven n

ten litres n one can of ten litres

is full water n another seven is

empty.

There is a one measurement of

three litres only two use

So divide five litres in each can

using three litre measurement

only none other than n there

should not be no one drop less or

variation

$\huge\mathcal\blue{Answer}$

4 + 4 liters) with the minimum number of water transfers. Note that the 8-liter bowl is initially filled with 8 liters of water and the other two bowls are empty - that is all water you have.

pour 5 litres from the 8-litre to the 5-litre bowl,

pour 3 litres from the 5-litre to the 3-litre bowl,

pour these 3 litres back to the 8-litre bowl,

pour the remaining 2 litres from the 5-litre to the 3-litre bowl,

pour 5 litres from the 8-litre to the 5-litre bowl,

pour the missing 1 litre from the 5-litre to the 3-litre bowl (there should be 4 litres left in the 5-litre bowl),

pour the 3 litres back from the 3-litre to the 8-litre bowl (and that's it - in 8-litre bowl 4 litres