U the area of the field.
The length of a rectangle is 1cm more than its breadth. The
diagonal is 29 cm. Find the area of the rectangle.
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Step-by-step explanation:
let the breadth be xcm then length will be x+1cm.as this is a right Angeled ∆ .eq.
{x}^{2} + ({x + 1)}^{2} = {29}^{2}x2+(x+1)2=292
(by solving the eq. we get )
x=-21 & x= 20
as distance cannot be -ve.
so,x=20cm breadth is20cm & length is 21cm.
area of ∆is 1/2×b×h
so,1/2×20×21=210cm
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