Question

U-tube is partially filled with mercury. Then, water is added to one arm of the tube and oil is added in the other. Draw the diagram and calculate the ratio of water and oil in the columns so that the mercury level is same within both arms of the tube. Density of mercury = 13600 kg m-3, density of water = 1000 kg m-3, and density of oil = 900 kg m-3.

Answer 1

Answer:

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Explanation:

Since the level of mercury in the two arms of the U-tube is same, therefore,

Pressure exerted by water columnin one arm =pressure exerted by liquid column in other arm

i.e., h

1

d

1

g=h

2

d

2

g

⇒

h

2

h

1

=

d

1

d

2

=

1000kgm −3 900kgm −3 = 109

.

Hence, the ratio of lengths of water and the liquid is 9:10.