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When a force vector F=(i+2j+k) N acts on
F=(i+2j+k) N acts on a body and produces a displacement of
S=(4i+j+7k)m, then the work done is
1) 9J
2) 13J
4) 1J
3) 5J
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3
Answer:
Option 2 is correct
Explanation:
Work done is dot product of displacement and force.
Given F=(i+2j+k) N
S=(4i+j+7k)m
W= F•S
W= (i+2j+k)•(4i+j+7k)
W= 4i•i+ 2j•j+ 7k•k
i•j=j•k=k•i=0
and i•i=j•j=k•k=1
therefore, W= 4+ 2+ 7= 13 J
Option 2 is correct
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