Physics, asked by hamadaali2002, 2 days ago

u(x) = (3x^2)-x find equilibrium position​

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Answered by aaronranjan
0

Answer:

x = 1/2

Explanation:

F=2x  

2

−3x−2

dx

dF

=4x−3<0

x<3/4 for stable equilibrium

x>3/4 for unstable equilibrium  

For stable F=0

2x  

2

−3x−2=0

2x  

2

−4x+x−2=0

2x(x−2)+1(x−2)=0

(2x+1)(x−2)=0

x=−  

2

1

,x=+2

Answered by Subhajit7523690
0

Answer:

Hope it is helpful to you

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