u(x) = (3x^2)-x find equilibrium position
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Answer:
x = 1/2
Explanation:
F=2x
2
−3x−2
dx
dF
=4x−3<0
x<3/4 for stable equilibrium
x>3/4 for unstable equilibrium
For stable F=0
2x
2
−3x−2=0
2x
2
−4x+x−2=0
2x(x−2)+1(x−2)=0
(2x+1)(x−2)=0
x=−
2
1
,x=+2
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