Question

ubinding
zeroes of the lolynomial
$4 {x }^{2} - 3x - 1$
​

Answer 1

Answer:

$4 {x}^{2} - 3x - 1 \\ = 4 {x}^{2} - (4 - 1)x - 1 \\ = 4 {x}^{2} - 4x + x - 1 \\ = 4x(x - 1) + 1(x - 1) \\ = (4x + 1)(x - 1)$

put x=0

(4×0+1)(0-1)

(0+1)(-1)

+1×-1

-1

put x=1

(4×1+1)(1-1)

4+1×0

5×0

=0

put x =-1

(4×-1+1)(-1-1)

(-4+1)×+1

-5×1

=-5

this is the answer for your question

hope this answer will help you

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