Udita’s father’s present age is five times her present age.Two years from now, Udita’s
age will be one-fousrth of her father’s present age.Find both udita’s her fathers present
age
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Answered by
2
Answer:
Let Udita Age is x
and his Father's Age be y
Hence, at present y=5x............(1)
and 2 Year from now
x+2=
4
y+2
⇒4x+8=y+2⇒4x−y=−6...............(2)
From (1) and (2)
4x−5x=−6⇒x=6
and y=5x=5∗6=30
Hence, Udita present age = 6
His father's present age = 30
Answered by
0
Answer:
Hence, Udita's present age = 6
His father's present age = 30
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