Question

uestion
1. A force of 7 N acts on an object.
The displacement is, say 8 m, in
the direction of the force
(Fig. 11.3). Let us take it that the
force acts on the object through
the displacement. What is the
work done in this case?​

Answer 1

Answer:

Here we are given with the value of applied force and displaces a body, for which we can say that work is done.

GiveN:

• Force applied on the body = 7 N
• Displacement of the body = 8 m in the direction of force.

Now we have to find the work done by the force.

The relation between the work, force & displacement,

$\rm{ \boxed{W = FS \cos( \theta) }}$

Where W is the work done

F is the force applied

And S is the displacement of the body.

So, let's start solving.

Since the displacement of the body is in the same direction of the force, we can say that angle between them is 0° :

$\rm{ \cos( \theta) = \cos(0 \degree) = 1}$

So, now the formula is W = Fs. Plugging the values to get the answer:

➝ W = FS

➝ W = 7 N × 8 m

➝ W = 56 Nm

Or Newton-metre is also known as Joules.

Work done by the force on the body:

$\large{ \boxed{ \sf{ \red{W = 56 \: Nm}}}}$

And we are done !!

Answer 2

Answer:

Here is your answer mate.

Explanation:

When a force F acts on an object to displace it through a distance S in its direction, then the work done W on the body by the force is given by: Work done = Force — Displacement W = F — S Where, F = 7 N S = 8 m Therefore, work done, W = 7 — 8 = 56 Nm = 56 J

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