Question

uestion numbers 13 to 22 carry 3 marks each.
3. Find HCF and LCM of 404 and 96 and verify that HCF LCM = Product of the two given numbers.​

Answer 1

Explanation :

Let a=404 and b=96

Let a=404 and b=96Expressing the number as a product of prime number

Let a=404 and b=96Expressing the number as a product of prime number404=2×2×101

Let a=404 and b=96Expressing the number as a product of prime number404=2×2×10196=2×2×2×2×2×3

Let a=404 and b=96Expressing the number as a product of prime number404=2×2×10196=2×2×2×2×2×3∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696

Let a=404 and b=96Expressing the number as a product of prime number404=2×2×10196=2×2×2×2×2×3∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696∴ HCF of 404 and 96 is 2×2=4

Let a=404 and b=96Expressing the number as a product of prime number404=2×2×10196=2×2×2×2×2×3∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696∴ HCF of 404 and 96 is 2×2=4Now HCF×LCM=4×9696=38784

Let a=404 and b=96Expressing the number as a product of prime number404=2×2×10196=2×2×2×2×2×3∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696∴ HCF of 404 and 96 is 2×2=4Now HCF×LCM=4×9696=38784Product of two given numbers 404×96=38784

Let a=404 and b=96Expressing the number as a product of prime number404=2×2×10196=2×2×2×2×2×3∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696∴ HCF of 404 and 96 is 2×2=4Now HCF×LCM=4×9696=38784Product of two given numbers 404×96=38784Hence HCM×LCM= product of two given numbers.

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