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An electrical iron uses a power of 1100 W when set to higher temperature. If set to lower
temperature, it uses 330 W power. Find out the electric current and the respective resistances
for the two settings. The iron is connected to a potential difference of 220 V.
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Answer:
P=VI
P1=220×I1
I1=1100/220
I1=5A
R1=V1/I1
R1=220/5=44ohm
power=potential difference×current
330=220×I2
I2=330/220=3/2
R2=220×2/3
440/3ohm
146.67ohm
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