Question

UIU AS SUHU. How old are Nuri and Sonu)
(ii) The sum of the digits of a two-digit number is 9. Also, ning times this number is
twice the number obtained by reversing the order of the digits. Find the number.​

Answer 1

$\huge{\mathbf{\red{\mid{\boxed{answer}\:{\mid}}}}}$

$\huge{\tt{\underline{Given:}}}$

=> Sum of a two digit number is 9.

=> 9 times that number is twice the number obtained by reversing the digits.

$\huge{\tt{\underline{Assuming:}}}$

=> Let the ones digit of that number be x and ones digit be y.

⠀

$\huge{\tt{\underline{Solution:}}}$

⠀

So, the number obtained will be -⠀⠀⠀⠀⠀⠀⠀⠀

$10x + y$

Here, we were given that :-

$x + y = 9...............eq(1)$

We were also given that :-

$9(10x + y) = 2(10y + x) \\ 90x + 9y = 20y + 2x \\ 90x - 2x = 20y - 9y \\ 88x = 11y \\ 88x - 11y =0 \\ 11(8x - y) = 0 \\ 8x - y = 0.......eq(2)$

On adding equations (1) and (2) :-

$(x + y) + (8x - y) = 9 + 0 \\ x + 8x - y + y = 9 \\ 9x = 9 \\ x = 1$

By putting x value in either of the equations :-

$x + y = 9 \\ 1 + y = 9 \\ y = 9 - 1 \\ y = 8$

So, x = 1 and y = 8.

Thus, putting both values in (10x + y) :-

$(10(1) + (8)) \\ 10 + 8 \\ 18.$

Hence, the number is $\huge{\boxed{18}}$.

Answer 2

Step-by-step explanation:

The answer is 18...

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