Physics, asked by Safal2613, 9 months ago

Ultraviolet light of 6.2eV falls on caesium surface (work function =1.2eV) the kinetic energy (in electron volts) of the fastest emitted is approximately 1.5eV 2.4ev
3.3eV
4.2eV

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Answered by fataldestiny

3

Answer:

option (1) 5ev

Explanation:

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