Umar has two copper pans, each containing 500cm3 of water. Pan A has a mass of 750g and pan B has a mass of 1.5kg. Which pan will require the least energy to heat the water to 100°C?
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The pan that will require the least energy to heat the water to 100°C is pan A.
hii mate
The given parameters;
volume of water, V = 500 cm³
mass of pan A = 750 g
mass of pan B = 1.5 kg = 1,500 g
final temperature of water, t = 100 ⁰C.
The total energy required to raise the temperature of the water from the initial temperature to final temperature is calculated as follows;
Q_t = Q_{pan} \ + Q_{water}Q
t
=Q
pan
+Q
water
Q = mc\Delta tQ=mcΔt
where;
m is the mass of each pan
The pan with more mass will require more energy while the pan with least mass will require less energy.
Thus, the pan that will require the least energy to heat the water to 100°C is pan A
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