Question

uncertainty in position of a 0.25 g particleis 10 ^5 . Then uncertainty in its velocity will be​

Answer 1

Answer:

uncertainty in velocity (Δv) ≥  2.1 X 10⁻²⁶ m/s

Explanation:

Given

mass of particle (m) = 0.25 g

uncertainty in position (Δx) = 10⁻⁵

uncertainty in velocity (Δv) = ??

Solution

By using Heisenberg's uncertainty principle

Δx m .Δv ≥ h/ 4π

where h = 6.6 X 10⁻³⁴ Js

Δv ≥ h/ 4π Δx m

By putting values

Δv ≥ 6.6 X 10⁻³⁴/ 4 (3.14) ( 10⁻⁵) (0.25)

Δv ≥  2.1 X 10⁻²⁶ m/s

uncertainty in velocity (Δv) ≥  2.1 X 10⁻²⁶ m/s