Uncertainty in position of an electron (mass = 9.1 × 10⁻²⁸ g)
moving with a velocity of 3 × 10⁴ cm/s accurate upto 0.001% will be
(use h/4????) in uncertainty expression where h = 6.626 ×10⁻²⁷ erg-second)
(a) 1.93 cm (b) 3.84 cm
(c) 5.76 cm (d) 7.68 cm
Answers
Answered by
8
YOUR ANSWER IS IN THE ATTACHMENT PLZZ REFER TO THE ATTACHMENT
And surely mark me BRAINLIEST
OPTION IS A
Attachments:
Answered by
1
Uncertainty in position of an electron is 1.932 cm
option (a) is correct.
•Heisenberg uncertainty principle :
• ∆x∆p ≥ h/4π or ∆x.m∆v ≥ h/4π
• ∆x.∆v ≥ h/4πm
• mass = 9.1 × 10⁻²⁸ g
• ∆v = (3×10⁴×0.001)/100 = 0.3 cm/s
• h = 6.626 ×10⁻²⁷ erg-second
• Using Heisenberg uncertainty v
principle
•∆x.0.3 = 6.626 ×10⁻²⁷/4π.9.1 × 10⁻²⁸
• ∆x = 66.26/12.56 × 9.1 × 0.3
• ∆x = 1.932 cm
Similar questions