Math, asked by ofrangenberg, 2 months ago

Under certain water​ conditions, the free chlorine​ (hypochlorous acid,​ HOCl) in a swimming pool decomposes according to the law of uninhibited decay. After shocking a​ pool, the pool​ boy, Geoff, tested the water and found the amount of free chlorine to be parts 2.7 per million​ (ppm). Twenty-four hours​ later, Geoff tested the water again and found the amount of free chlorine to be 2.4 ppm. What will be the reading after days​ (that is, ​hours)? When the chlorine level reaches 1.0​ ppm, Geoff must shock the pool again. How long can Geoff go before he must shock the pool​ again?

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Answered by ayeshaalam38
1

hope it will help you.

thanks.

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