Question

under root 1+cos theta/1-cos theta=cosec theta+cot theta

Answer 1

Hope this helps you ☺☺

By rationalise ,we can solve .

Answer 2

Answer:

Step-by-step explanation:

To prove: $\sqrt{\frac{1+cos{\theta}}{1-cos{\theta}}}=cosec{\theta}+cot{\theta}$

Taking the LHS of the above equation,

$\sqrt{\frac{1+cos{\theta}}{1-cos{\theta}}}=\sqrt{\frac{1+cos{\theta}}{1-cos{\theta}}{\times} \frac{1+cos{\theta}}{1+cos{\theta}}}$

=$\sqrt{\frac{(1+cos{\theta})^{2}}{1-cos^{2}{\theta}}}$

=$\sqrt{\frac{(1+cos{\theta})^{2}}{sin^{2}{\theta}}}$

=$\frac{1+cos{\theta}}{sin{\theta}}$

=$cosec{\theta}+cot{\theta}$=RHS

Hence proved.