under root 1 + sin theta / 1 - sin theta + under root 1 minus sin theta / 1 + sin theta is equals to 2 sec theta
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√1-sin theta/√1+sin theta
√1-sin theta × √1+sin theta/√1+sin theta × √1+sin theta(its because of resnilization)
(1-sin theta) ^2/(1+ sin theta) ^2
√(1-sin theta)^2/√cos^2 theta
1-sin theta/cos
1/cos theta-sin theta/cos theta
Sec theta-tan theta thats it..... Please check your question I think its not equal to 2 sec theta otherwise contact your teacher.
√1-sin theta × √1+sin theta/√1+sin theta × √1+sin theta(its because of resnilization)
(1-sin theta) ^2/(1+ sin theta) ^2
√(1-sin theta)^2/√cos^2 theta
1-sin theta/cos
1/cos theta-sin theta/cos theta
Sec theta-tan theta thats it..... Please check your question I think its not equal to 2 sec theta otherwise contact your teacher.
shiks1:
ok
thank
i will confirm this que again to my teacher
Okey
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