(Under root 2 m +under root 3 n )whole square
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Answer:
2M^2+3N^2+2√6MN
Step-by-step explanation:
(√2M+√3N)^2
using formula (a+b) ^2=a^2+b^2+2ab,we get
=(√2M)^2+(√3N)^2+2*√2M*√3N
=2M^2+3N^2+2√6MN
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