Question

under root (27-10 root 2)​

Answer 1

Described in the image

Answer 2

Answer is $5 - \sqrt 2$

Step-by-step explanation:

$\sqrt (27 - 10 \times \sqrt2)$

= $\sqrt (25 - 10\sqrt + 2)$

= $\sqrt (5^2 - 2 \times 5 \times \sqrt2 + (\sqrt 2)^2)$

• Using the identity - $(a - b)^2 = a^2 -2ab + b^2$

= $\sqrt (5^2 - 2 \times 5 \times \sqrt2 + (\sqrt 2)^2)$

= $\sqrt (5 - \sqrt 2)^2$

= $5 - \sqrt 2$