Question

under root 3-2under root 2​

Answer 1

Question:-

under root 3-2under root 2​ simplify ?

Answer:-

$= \sqrt{3-2\sqrt{2} } \\\\= \sqrt{3-2\sqrt{2} } \\\\= \sqrt{(\sqrt{2})^2 + (1)^2 - 2(\sqrt{2})*(1) } \\\\as we know that \\ \\ a^2 + b^2 - 2ab = (a + b )^2\\= \sqrt{(\sqrt{2} - 1 )^2} \\\\= \sqrt{2} - 1$

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