Math, asked by manishkum6671, 1 year ago

Under root 6 upon Under root 2 + under root3

Anonymous: ___k off

Answers

Answered by sabhya18

1

by rationalization method

root6/(root2+root3)×(root2-root3)/(root2-root3)

(root6 (root2-root3))/2-3

-1 (2root3-3root2) Ans

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