Question

Under root sec a-1 divide by sec a + 1 + sec a+ 1 ÷ sec a-1 = 2cosec a

Answer 1

Answer:

Prove: under root (sec theta-1/sec theta+1) + under root (sec theta+1/sec theta-1) = 2 Cosec theta?

Missing: a+ ‎| Must include: a+

0 votes

I will use A in pace of theta for ease Consider (sec A -1)/(sec A +1) = (1-cos A)/(1+cos ... More

2 votes

√{(sec β -1)/(secβ +1)} = √{(1 - cosβ)/(1+cosβ)} (by dividing every term by ... More

2 votes

[math]\sqrt{\dfrac{sec \theta-1}{sec \theta+1}}+ \sqrt{\dfrac{sec \theta+1}{sec \theta-1}}[/math] ... More