Question

under root x - 1 ka whole square is equal to 8 minus under root 28

Answer 1

The value of $x =9-2\sqrt{7}$.

Step-by-step explanation:

We have,

$(\sqrt{x-1})^{2} =8-\sqrt{28}$

To find, the value of x = ?

∴$(\sqrt{x-1})^{2} =8-\sqrt{28}$

⇒$x-1 =8-\sqrt{28}$

⇒$x =8-\sqrt{28}+1$

⇒$x =9-\sqrt{28}$

⇒$x =9-2\sqrt{7}$

∴ $x =9-2\sqrt{7}$

Hence, the value of $x =9-2\sqrt{7}$.