Math, asked by manymany, 1 year ago

under root3 is a prime number

Answers

Answered by Swarup1998
2

√3 is not a prime number. It is an irrational number.

Extra:

  • Irrational numbers. The numbers which cannot be expressed in the form of a fraction of the form a/b where both a and b are integers with non-zero b, are called irrational numbers.
  • Examples. √2, √3, √5, √7, ... .
  • You can note one thing that, the irrational numbers are simply square root of the prime numbers.

  • Prime numbers. The numbers which have factors 1 and itself, are called prime numbers.
  • Examples. 2, 3, 5, 7, ... .
Answered by Anonymous
4

Answer:

  • No \sf{\sqrt{3}} is not a prime number.

  • \sf{\sqrt{3}} is a Irrational number.

Prime number:

  • Prime numbers are the numbers which are also natural numbers.

  • Prime numbers have only 2 factors.

  • The 2 factors are: 1 and the number itself.

Example:

  • 1, 3, 5, 7, etc In numbers.

  • \sf{\sqrt{1}}, \sf{\sqrt{3}}, \sf{\sqrt{5}}, \sf{\sqrt{7}}, etc In under roots.

Irrational number:

  • Irrational numbers are the numbers which can't be express as fraction in the form of p/q.

  • π (pi) is one of the best example for irrational number.
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