Question

Under the action of a force, a 2 kg body moves
such that its position x as a function of time is
given by: x=t3/3, where x is in metre and t in
seconds. The work done by the force in the first
two seconds is:​

Answer 1

what your question is missing some information please come back with fully detailed question

Answer 2

Answer:

hey mate here's ur answer...

✌✌ HOPE IT HELPS YOU ✌✌

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MNB...