Under the action of a force, a 2kg body moves such that it's position x as a function of time to is given by x=t^3/3,where x is in meter and t in seconds.the work done by the force in the first two seconds us
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Under the action of a force a 2 kg body moves such that its position
Under the action of a force, a `2 kg` body moves such that its position x as a function of time is given by `x =(t^(3))/(3)` where x is in metre and t in second. The work done by the force in the first two seconds is .
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