under what condition the root of the below quadratic equation will be real and equal X square + b is equal to q
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Answer:the roots will be real and equal if b is either 0 or it is a negative number where the positive equivalent of the number should be a perferct square of a real number
Step-by-step explanation:
x²+b=0
x²=-b
x=√-b
Roots will be real only if b is 0 where the roots will also be 0,0
Other condition where roots will be real and equal is when b is negative
So x=√b
Therefore the roots will become real
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