Understqnding quadilaterals
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ʜᴇʟʟᴏ ᴍᴀᴛᴇ!
Ad we know that some of adjacent angles of a quadrilateral is 180°, so
( 2y + 10° ) + ( 3y - 40° ) = 180°
5y - 30° = 180°
5y = 180° + 30°
y = 210° / 5 or 42°
So 1st adjacent side ( 2y + 10° ) = (2)(42°) + 10°
= 94°
Another angle( 3y - 40° ) = (3)(42°) - 40°
= 126° - 40° = 86°
Now, as mentioned quadrilateral is parallelogram, so opposite angles are equal
So required angles are = 94°, 86°, 94°, 86°
Hope it helps
Ad we know that some of adjacent angles of a quadrilateral is 180°, so
( 2y + 10° ) + ( 3y - 40° ) = 180°
5y - 30° = 180°
5y = 180° + 30°
y = 210° / 5 or 42°
So 1st adjacent side ( 2y + 10° ) = (2)(42°) + 10°
= 94°
Another angle( 3y - 40° ) = (3)(42°) - 40°
= 126° - 40° = 86°
Now, as mentioned quadrilateral is parallelogram, so opposite angles are equal
So required angles are = 94°, 86°, 94°, 86°
Hope it helps
shelter:
U r genius
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