Question

Uniform magnetic field of 100 Gauss in East to West direction .44 CM wire with current carrying capacity of 10 ampere. What is the shape and orientation of the loop of this wire, which yields maximum turning effect on loop and Find maximum torque.

Answer 1

Answer:

Torque = 1.53 x 10⁻³ Nm

Explanation:

Given:

Magnetic Field(B) = 100 Gauss = 0.01 T

Length of wire(L) = 44 cm = 0.44 m

Current (I) = 10 A

torque (τ) = ?

According to question,

angle (θ) made by the plane of the coil is perpendicular to the direction of magnetic field

i.e. θ = 90° which means the coil is circular shaped.

Therefore,

L = 2πr

or, 0.44 = 2πr

or, 0.44 / 2π = r

∴ r = 0.07 m

Now,

Area of the coil = πr² = π x (0.07)² = 0.0153 m²

We have,

τ = B I N A sinθ

τ = 0.01 x 10 x 1 x 0.0153 x sin90

τ = 1.53 x 10⁻³ Nm