Question

uniform sphere of mass m and radius R rolls without slipping down an inclined plane set at an angle to the horizontal. Find kinetic energy of sphere t sec after the beginning of motion​

Answer 1

Answer:

$\frac{1}{2} (m)(gt) {}^{2} \: where \: g \: is \: accelaration \: due \: to \: gravity$

Explanation:

Mass of the body is m

U =o

Time=0 and a=g

K. E =

$\frac{1}{2} mv {}^{2}$

$v = u + at \:$

$v = 0 + gt$

$v = gt$

$ke \: = \frac{1}{2} mv {}^{2}$

$\frac{1}{2} \times m \times (gt) {}^{2}$

$\frac{m {g}^{2} t {}^{2} }{2}$