Question

unile theproperty which you have observed.Tous write the proof of this propertyTheorem: perpendicular drawn from the centre of a circle on its chord bisects the chordTo prove i seg APE seg BPseg AB is a chord of a circle with centre oseg Op 1 chord ABGivenPB: Draw seg OA and seg ORIn A OPA and AOPBLOPA ZOPBseg Op I chord ABsog OP = seg OPcommon sidehypotenuse OA hypotenuse OBradii of the same circle... A OPA = A OPB hypotenuse side theoremseg PA seg PB0.3.0.1.Fig. 6.4​

Answer 1

Answer:

To prove that the perpendicular from the centre to a chord bisect the chord.

Consider a circle with centre at O and AB is a chord such that OX perpendicular to AB

To prove that   AX=BX

In ΔOAX and ΔOBX

∠OXA=∠OXB  [both are 90 ]

OA=OB  (Both  are radius of circle )

OX=OX  (common side )

ΔOAX≅ΔOBX

AX=BX  (by property of congruent triangles )

hence proved.