Unit vector along the direction of line 2(x-2)=(y+1)=(3-1) is
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If point P is (2,4,4) and Q is (-3,2,2), the vector PQ would be (-5,-2,-2). To find the unit vector, divide vector PQ by its magnitude. ∣∣∣∣∣∣−−→PQ∣∣∣∣∣∣ would be √(−5)2+(−2)2+(−2)2)=√33. Hence unit vector would be
(1√33)⎛⎜⎝−5−2−2⎞⎟⎠
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