Question

units?
50. The volume (V) of a mass of gas varies directly as
its absolute temperature (T) and inversely as the
pressure (P) applied to it. The gas occupies a vol-
ume of 400 ml when the temperature is 150 k and
pressure is 240 Pa. What is the temperature of gas
whose volume and pressure are 250 ml and 320 Pa
respectively?​

Answer 1

Answer:

Temperature T2 = 125 K

Step-by-step explanation:

Data:

Volume = V1 = 400 ml

Temperature = T1 = 150 K

Pressure = P1 = 240 Pa

V2 = 250 ml

P2 = 320 Pa

Formula :

V = k T / P

Required :

Temperature = T2 = ?

Calculation:

We are know that

     V = k T / P

To find the value of k we use all given data where K in unknown

    V1 = K T1 / P1

Putting values we get

     400 = K 150 / 240

  K(150) = (400)(240)

          K = 400(240) / 150  

          K = 640 ml Pa/K

Now using the value of K for second data where T is unknown

We know that

      V = k T / P

      V2 = K T2 / P2

Putting values we get

    250 = 640 T2 / 320

       T2 = 250(320)/640  

      T2 = 125 K

Hence

Temperature T2 = 125 K

Answer 2

Answer:

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