Math, asked by Ziasajid8290, 10 months ago

Unni has a cubicle room of his own whose total surface area is 216m. Find the cost of distempering the four walls of the room at the rate of Rs.40 per m².
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Answered by Anonymous
0

Refer to the above attachment

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Answered by silentlover45
1

\large\underline\mathrm\red{Given:-}

  • \small\mathrm{Total \: surface \: area \: of \: the \: cubical \: room  \: = \: 216 \:  {m}^{2}}

\large\underline\mathrm\red{To \: find}

  • \small\mathrm{What \: is \: the \: cost \: of \: distempering \: the \: four \: walls \: of \: the \: room \: at \: the \: rate \: of \: 40 \: per \: {m}^{2}?}

\large\underline\mathrm\red{Solution}

  • \small\mathrm{Let \: the \: side \: of \: the \: cubical \: room \: be \: x \: m}

  • \small\mathrm{We \: know \: that \: the \: formula \: for \: finding \: the \: Total \: surface \: area \: of \: the \: cubical \: room \: is:-}

\large\underline\mathrm\red{{\star \: AREA = 6 {(side)}^{2} \: \star }}

\large\underline\mathrm\red{According \: to \: questions:-}

\small\mathrm{On \: putting \: the \: given \: values \: in \: the \: formula, \: we \: get}

\small\mathrm{⇢{216} = {6(x)}^{2}}

\small\mathrm{⇢{216} = {6x}^{2}}

\small\mathrm{⇢{216}/{6} = {x}^{2}}

\small\mathrm{⇢{36} = {x}^{2}}

\small\mathrm{⇢ root{36} = {x}}

\small\mathrm{⇢{6} m = {x}}

\large\underline\mathrm\red{The \: side \: of \: the \: cubical \: room \: is \: 6m}

\small\mathrm{Now, \: we \: have \: to \: find \: the \: area \: of \: four \: falls.}

\small\mathrm{We \: know \: that \: the \: formula \: for \: finding \: the \: Curved \: surface \: area \: of \: the \: cubical \: room \: is:-}

\large\underline\mathrm\red{\star \: AREA = 4 {(side)}^{2} \: \star}

\large\underline\mathrm\red{According \: to \: questions:-}

\small\mathrm{On \: putting \: the \: given \: values \: in \: the \: formula, \: we \: get}

\small\mathrm{⇢{Area = {4} × {(6)}^{2}}}

\small\mathrm{⇢{Area} = {4} × {36}}

\small\mathrm{{\star \: Area = 144 \: {m}^{2} \: \star }}

⇢ 1 m² = Rs. 40

⇢ 144 m² =  40 ×  144 =  Rs.5760

❝Hence, the cost of distempering the 4 walls of the room is  Rs.5760❞

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