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Question (Non-anonymou: question 1 (4 Points)
Q 25
Find the number of terms of the A. P 6, 13, 20.....216. If 1 is added to
each term of this AP then find the sum of all the terms of the A P thus
obtained
Answers
Given : A. P 6, 13, 20.. ...216
To Find : Number of Terms
1 is added to each term of this AP then find the sum of all the terms of the A P obtained
Solution:
A. P
6, 13, 20... ..216
a = 6
d = 7
last term = 216
=> 216 = 6 + (n - 1)7
=> 210 = (n - 1)7
=> 30 = n - 1
=> 31 = n
Number of terms = 31
Sum of all terms
= (31/2)(6 + 216)
= 31(3 + 108)
= 31(111)
= 3441
If 1 s added to each term then sum will increase by 31 as there are 31 terms
3441 + 31 = 3472
Or
AP will be
7 , 14 , 21 , ... .. .. , 217
a = 7 d = 7 n = 31
Sum = (31/2)(7 + 217)
= (31/2)(224)
= 31 * 112
= 3472
number of terms = 31
Sum obtained from new AP = 3472
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Answer:
A. P
6, 13, 20... ..216
a = 6
d = 7
last term = 216
=> 216 = 6 + (n - 1)7
=> 210 = (n - 1)7
=> 30 = n - 1
=> 31 = n
Number of terms = 31
Sum of all terms
= (31/2)(6 + 216)
= 31(3 + 108)
= 31(111)
= 3441
Step-by-step explanation: