upon mixing equal volume of 0.1M HCl and 0.2 M H2SO4 the concentration of H+ in the resulting solution is
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Molarity = no of moles of solute[H+]/ volume of solution
No of moles of [H+] for HCl = 0.3*0.1 = 0.03
No of moles of [H+] for H2SO4 = 0.2*2*0.3 = 0.12 (since there are two moles of H+ in a mole H2SO4
Total no of moles of [H+] = 0.15
Total volume of solution = 300ml = 0.3L
Thus Molarity = 0.15/0.3 = 0.5moles/L
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