UR
(i)
A soap film is on a rectangular wire ring of size 2cm x 3cm. If the size
of the film is changed to 3cm x 3cm, calculate the work done in this
process. (the surface tension of soap solution is 3.0x10-²Nm).
Answers
work done in the process is 1.8 × 10^-5 J
initial area of film, A_i = 2cm × 3cm = 6 cm²
final area of film, A_f = 3cm × 3cm = 9cm²
change in area, ∆A = A_f - A_i
= 9 cm² - 6 cm²
= 3 cm² = 3 × 10-⁴ m²
work done , W = change in area × surface tension
but A soap has two surface so,
workdone in the given process, W = 2∆A.T
= 2 × 3 × 10-⁴ m² × 3.0 × 10-² N/m
= 18 × 10^-6 Nm = 1.8 × 10^-5 J
also read similar questions : There is a soap film on a rectangular frame of wire of area 4 cm x 4 cm. If the area of the frame is increased to 4 cm x...
https://brainly.in/question/6995029
There is a soap film on a rectangular frame of wire of area 4 cm x 4 cm. If the area of the frame is increased to 4 cm x...
https://brainly.in/question/6568060
Answer:
workdone in the given process, W = 2∆A.T
= 2 × 3 × 10-⁴ m² × 3.0 × 10-² N/m
= 18 × 10^-6 Nm = 1.8 × 10^-5 J