Urea forms an ideal solution in water .Determine the vapour pressure of aqueous solution containing 10% by mass of urea of 4∘C.(Vapour pressure of water,at 40∘C=55.3 mm Hg)
Answers
Answered by
1
Answer:
Vapour pressure of the solution is 53.516 mm of Hg
Explanation:
SUGGESTION :
I think both Temperatures must be given 40°C
.
FORMULAE :
1) Psol = P°water × Xwater
P°water = 55.3 mm Hg
Xwater = mole fraction of water in solution.
2) Xwater is to be found by formula given in attached photo.
Procedure :
That gives,
Xwater = 90÷18 = 30
90÷18 + 10÷60 31
Since,
GMWwater = 18g
GMWurea = 60g
mass of water taken. = 90% total mass
mass of urea taken. = 10% total mass
Answer :
Therefore, Psolution = 55.3× 30 = 53.516 mm Hg
31
Attachments:
Similar questions