Urea forms ideal solution in water determine vapour pressure of aqueous solution containing 10 percent
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Mass of urea = 10g
Mass of water = 90g
Moles of urea =10g/60gmol−1=16
Moles of water =90/18=5
Mole fraction of water
xA=5/5+26=5/31
Vapour pressure of solution
P=P∘A.xA
=55.3×5/31
P=53.52 mm Hg
The mole fraction will be (30/31)
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