Question

URGENT HELP NEEDED FROM AN EXPERT

Q1 The position 'x' of the particle varies with time as x= at^2- b^3.
Calculate the acceleration after two seconds​

Answer 1

Answer:

x=at

2

−bt

3

⇒ Velocity =

dt

dx

=2at−3bt

2

Acceleration=

dt

2

d

2

x

=

dt

d

(2at−3b

2

)=2a−6bt

or a=2a−6bt

Making a=0

⇒2a=6bt

⇒t=dfrac2a6b=

3b

a

.