URGENT.... if A:B=2:3 B:C=4:5 C:D=6:7 then find the ratio of A:B:C:D
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refer the pic
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Anonymous:
Y have u multiplied by 3 4 6 and then divided by 3
Plz explain in detail
to equalise the B in A:B and B:C we have to multiply
From where 15 came
And y dividing by 3
and the ratio is always have to be in its least terms so we take 3 as common in that ratio and divided whole ratio by 3 to get it into it's least terms
Thank uh sooo much
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Given : A : B = 2 : 3 , B : C = 4 : 5, and C : D = 6 : 7 , So
AB = 23 , BC = 45 and CD = 67
Here , LCM ( 3 , 5 and 7 ) = 105 , So
AB = 70105 , BC = 84105 and CD = 90105
Here we can see CD = 90105 , Here C as 90 ,So we want BC = x90 , But we have BC = 84105 , So
x90 = 84105⇒x = 84105× 90⇒x = 847× 6⇒x = 12 × 6⇒x = 72
Therefore,
BC = 7290
We have : AB = 70105 , Now we want to get it B = 72 , So
y72 = 70105⇒y = 70105×72⇒y = 23 × 72⇒y = 2 × 24⇒y = 48
So,
AB = 4872 , Then
A : B : C : D = 48 : 72 : 90 : 105
A : B : C : D = 16 : 24 : 30 : 35 ( Ans )
AB = 23 , BC = 45 and CD = 67
Here , LCM ( 3 , 5 and 7 ) = 105 , So
AB = 70105 , BC = 84105 and CD = 90105
Here we can see CD = 90105 , Here C as 90 ,So we want BC = x90 , But we have BC = 84105 , So
x90 = 84105⇒x = 84105× 90⇒x = 847× 6⇒x = 12 × 6⇒x = 72
Therefore,
BC = 7290
We have : AB = 70105 , Now we want to get it B = 72 , So
y72 = 70105⇒y = 70105×72⇒y = 23 × 72⇒y = 2 × 24⇒y = 48
So,
AB = 4872 , Then
A : B : C : D = 48 : 72 : 90 : 105
A : B : C : D = 16 : 24 : 30 : 35 ( Ans )
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