Question

Urgent
Ionic conductance of Ba2+ and Cl- are 127 and 76 ohm inverse cm2 ​​​​at infinite dilution. The equivalent conductance of BaCl2 at infinite dilution will be

Answer 1

279 is the right answer.

Answer 2

Given:

Ionic Conductance of $Ba^{2+}$ = 127 $ohm^{-1} cm^2 Eq^{-1}$

Ionic Conductance of $Cl^-$ = 76 $ohm^{-1} cm^2 Eq^{-1}$

To find:

Equivalent conductance of $BaCl_2$ at infinite dilution = ?

Formula to be used:

Equivalent conductance = $\frac{1}{2}$×ionic conductance of cation + Ionic conductance of anion

Calculation:

As ionic conductance of barium ion and chlorine ion are given, the equivalent conductance of $BaCl_2$ can be calculated.

Equivalent conductance of $BaCl_2$ at infinite dilution = $\frac{1}{2}$×ionic conductance of $Ba^{2+}$ + Ionic conductance of $Cl^-$

Equivalent conductance of $BaCl_2$  = $\frac{1}{2}\times 127+76$

Equivalent conductance of $BaCl_2$  = 63.5+76 = 139.5

Conclusion:

∴ Equivalent conductance of BaC$l_2$ at infinite dilution will be 139.5 $ohm^{-1} cm^2$

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