urgent tell question no. 6
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There is only q7
For that, solution is,
Given that a-3b=20°
Then a=20+3b -----1equation
As we know that the sum of angles of a triangle is 180°
Then
a+b =180°
Put the value of a from equation 1
20°+3b+b =180
4b=180-20
4b=160
b=160/4
b =40
Then the angles are
40 and 180-40=140°
I hope this will help you
For that, solution is,
Given that a-3b=20°
Then a=20+3b -----1equation
As we know that the sum of angles of a triangle is 180°
Then
a+b =180°
Put the value of a from equation 1
20°+3b+b =180
4b=180-20
4b=160
b=160/4
b =40
Then the angles are
40 and 180-40=140°
I hope this will help you
Answered by
0
AC forms a straight line as AB, AC are opposite rays.
We know that angles on a straight line equals a straight angle .
Now, a + b = 180°
Given, a - 3b = 20
a = 20+ 3b .
Now, (20 + 3b ) + b = 180
20 + 4b = 180
4b = 160
b = 40°
So, a = 20 + 3(40) = 140°
Hope helped!
We know that angles on a straight line equals a straight angle .
Now, a + b = 180°
Given, a - 3b = 20
a = 20+ 3b .
Now, (20 + 3b ) + b = 180
20 + 4b = 180
4b = 160
b = 40°
So, a = 20 + 3(40) = 140°
Hope helped!
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