URGENTLY NEEDED PLEASE
If -2 and 3 are the zeros of the quadratic polynomial x2 + (a + 1)x + b then
Answers
Answered by
1
Answer:
-2 and 3 are zeroes.
substitute in the equation
=>(-2)
(-2)²+(a+1)-2+b=0
4-2a-2+b=0
-2a+b+2=0
2a-b-2=0
=>(3)
(3)²+(a+1)3+b=0
9+3a+3+b=0
3a+b+12=0
solve formed equations
We get
a=2
b=-18
Answered by
0
Answer:
-2 and 3 are zeroes.
substitute in the equation
=>(-2)
(-2)²+(a+1)-2+b=0
4-2a-2+b=0
-2a+b+2=0
2a-b-2=0
=>(3)
(3)²+(a+1)3+b=0
9+3a+3+b=0
3a+b+12=0
solve formed equations
We get
a=2
b=-18
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