Question

URGENTLY NEEDED PLEASE


If -2 and 3 are the zeros of the quadratic polynomial x2 + (a + 1)x + b then

Answer 1

Answer:

-2 and 3 are zeroes.

substitute in the equation

=>(-2)

(-2)²+(a+1)-2+b=0

4-2a-2+b=0

-2a+b+2=0

2a-b-2=0

=>(3)

(3)²+(a+1)3+b=0

9+3a+3+b=0

3a+b+12=0

solve formed equations

We get

a=2

b=-18

Answer 2

Answer:

-2 and 3 are zeroes.

substitute in the equation

=>(-2)

(-2)²+(a+1)-2+b=0

4-2a-2+b=0

-2a+b+2=0

2a-b-2=0

=>(3)

(3)²+(a+1)3+b=0

9+3a+3+b=0

3a+b+12=0

solve formed equations

We get

a=2

b=-18