Use a four step procedure to solve the following problem. How much water must be added to gallon of 10% saline solution to create a 2% solution
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1. There is 1 gallon of % solution.
Answer:
Given that 10% saline solution so answer is "1 gallon of 10% solution."
2. There is % saline in water.
Answer:
Water is pure so answer is "0% saline in water"
3. The equation is .
Answer:
(0% of x gallon water) + (10% of 1 gallon saline solution) = 2% of mixture
0(x)+0.10(1)=0.02(1+x)
Hence required equation is 0(x)+0.10(1)=0.02(1+x)
4. The answer is gallons.
Answer:
Now solve above equation to find value of x
0(x)+0.10(1)=0.02(1+x)
0+0.10=0.02+0.02x
0.10=0.02+0.02x
0.10-0.02=0.02x
0.08=0.02x
0.08/0.02=x
4=x
Hence 4 gallons of water is needed.
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