Math, asked by isaacvanbuskirk961, 10 months ago

Use a four step procedure to solve the following problem. How much water must be added to gallon of 10% saline solution to create a 2% solution

Answers

Answered by nhkmk786
4
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1. There is 1 gallon of % solution.

Answer:

Given that 10% saline solution so answer is "1 gallon of 10% solution."


2. There is % saline in water.

Answer:

Water is pure so answer is "0% saline in water"


3. The equation is .

Answer:

(0% of x gallon water) + (10% of 1 gallon saline solution) = 2% of mixture

0(x)+0.10(1)=0.02(1+x)

Hence required equation is 0(x)+0.10(1)=0.02(1+x)


4. The answer is gallons.

Answer:

Now solve above equation to find value of x

0(x)+0.10(1)=0.02(1+x)

0+0.10=0.02+0.02x

0.10=0.02+0.02x

0.10-0.02=0.02x

0.08=0.02x

0.08/0.02=x

4=x

Hence 4 gallons of water is needed.

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